Difficult partial differential Problem

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SUMMARY

The discussion centers on solving the partial differential equation given by $$\frac {\partial }{\partial t}A\left( y,t \right) +6\,\Lambda\,\Omega\, \left( {y}^{2}-y \right) \sin \left( t \right) ={\frac {\partial ^{2}}{\partial {y}^{2}}}A \left( y,t \right)$$ with boundary conditions $$\frac{\partial }{\partial y}A \left( t,0 \right) ={\frac {\partial }{\partial y}}A \left( t,1 \right) =0$$. The solution is derived as $$A \left( y,t \right) =6\,\Lambda\, \left( \Im \right) \, \left\{ [{\frac {i\sinh \left( \alpha\,y \right) }{\alpha}}-{\frac {i \left( 1-\cosh \left( \alpha \right) \right) \cosh \left( \alpha\,y \right) }{\alpha\,\sinh \left( \alpha \right) }}+i{y}^{2}-iy+2\,{\Omega}^{-1}]{{\rm e}^{it}} \right\}$$, where $$\alpha=1/2\, \left( 1+i \right) \sqrt {2}\sqrt {\Omega}$$. The recommended approach for solving this diffusion equation with a periodic source term is the separation of variables method, with additional resources provided for further exploration.

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Problem:
$${\frac {\partial }{\partial t}}A\left( y,t \right) +6\,\Lambda\,\Omega\, \left( {y}^{2}-y \right) \sin \left( t \right) ={\frac {\partial ^{2}}{\partial {y}^{2}}}A \left( y,t \right)$$
$${\frac{\partial }{\partial y}}A \left( t,0 \right) ={\frac {\partial }{\partial y}}A \left( t,1 \right) =0$$
Boundary condition
$${\frac{\partial }{\partial y}}A \left( t,0 \right) ={\frac {\partial }{\partial y}}A \left( t,1 \right) =0$$
ANSWER OF THIS EQUATION IS
$$A \left( y,t \right) =6\,\Lambda\, \left( \Im \right) \, \left\{ [{\frac {i\sinh \left( \alpha\,y \right) }{\alpha}}-{\frac {i \left( 1-\cosh \left( \alpha \right) \right) \cosh \left( \alpha\,y \right) }{\alpha\,\sinh \left( \alpha \right) }}+i{y}^{2}-iy+2\,{\Omega}^{-1}]{{\rm e}^{it}} \right\}$$
Where, $$\alpha=1/2\, \left( 1+i \right) \sqrt {2}\sqrt {\Omega}$$
attempt at a solution

Maple didn't give an answer. I don't know how to get this kind of solution.
IMG_20171223_030037.jpg
 

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This is a diffusion equation with some periodic source term. You should try separation of variables for this. There is an example on the wiki page, but searching for separation of variables of nonhomogeneous heat equation will lead to many extensive examples.
You could start here:
https://en.wikipedia.org/wiki/Separation_of_variables#Example:_nonhomogeneous_case
http://www.math.psu.edu/wysocki/M412/Notes412_10.pdf
 
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Thank you, sir. I got it. This thread can be closed now.
 

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