What is the Hamiltonian operator for a decaying Carbon-14 atom?

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Discussion Overview

The discussion revolves around the Hamiltonian operator for a decaying Carbon-14 atom, specifically in the context of beta decay. Participants explore the quantum mechanical aspects of this decay process and seek clarification on related concepts.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant asks for the Hamiltonian operator related to a decaying Carbon-14 atom.
  • Another participant inquires about the type of decay, suggesting that if it is Fermi decay (beta decay), one should consider H(i to f).
  • A participant confirms it is beta decay but expresses a lack of familiarity with quantum mechanics and the meaning of "take H(i to f)."
  • Another participant provides a qualitative description of beta decay, explaining the conversion of a proton to a neutron and the emission of a beta particle and a neutrino, while referencing Fermi’s Golden rule for a quantum-mechanical description.
  • Links to external resources are shared for further reading on beta decay and the Hamiltonian related to such processes.

Areas of Agreement / Disagreement

Participants generally agree on the nature of beta decay but have differing levels of understanding regarding the Hamiltonian operator and its application in this context. The discussion remains unresolved regarding the specific formulation of the Hamiltonian operator.

Contextual Notes

Some participants express uncertainty about the terminology and concepts related to quantum mechanics and the Hamiltonian operator, indicating a potential gap in foundational knowledge for some contributors.

Joshua L
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Hey, here's a quick question:

What is the Hamiltonian operator corresponding to a decaying Carbon-14 atom.

Any insight is quite appreciated!
 
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what type of decay ? if its fermi decay ( beta decay) take H(i to f) !
 
Yes, it's beta decay. But, unfortunately, I haven't taken any quantum mechanics courses yet. I know the concept and some general examples of the Hamiltonian, but I do not know what "take H(i to f)" means.
 
Joshua L said:
But, unfortunately, I haven't taken any quantum mechanics courses yet.

But a qualitative understanding of Mechanism of decay has to be made up;

The beta decay is a radioactive decay in which a proton in a nucleus is converted into a neutron (or vice-versa).

In the process the nucleus emits a beta particle (either an electron or a positron) and quasi-massless particle, the neutrino.
The properties of beta decay can be understood by studying its quantum-mechanical description via Fermi’s Golden rule,

as done for gamma decay. 2π |� | W = ψ Vˆ h |ψ | 2 f i� ρ(Ef ) After all, we are familiar with charged particles that produce (create) an e.m. field. However in QM photons are also particles, and by analogy we can have also creation of other types of particles, such as the electron and the neutrino.
see details
Page 101-<http://ocw.mit.edu/courses/nuclear-engineering/22-02-introduction-to-applied-nuclear-physics-spring-2012/lecture-notes/MIT22>
http://oregonstate.edu/instruct/ch374/ch418518/Chapter 8 Beta Decay-rev.pdf
 
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