What is the height of the cliff?

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Homework Help Overview

The problem involves determining the height of a cliff based on the motion of two rocks dropped and thrown by a llama farmer. The scenario includes kinematics principles and the effects of gravity on the rocks' motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of kinematics equations and the implications of time differences between the two rocks. Questions arise regarding the sign convention for velocity and the direction of gravitational acceleration.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem, including the setup of equations and the interpretation of physical concepts such as velocity and acceleration. Some guidance has been offered regarding the equations to use, but no consensus has been reached on the final approach.

Contextual Notes

Participants express uncertainty about the final velocity, height, and time, indicating a lack of complete information to solve the problem directly. The discussion also highlights the importance of understanding sign conventions in physics.

adidab12
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1. To determine how high a cliff is, a llama farmer drops a rock, and then 0.800 s later, throws another rock straight down at a velocity of −10.0 m/s. Both rocks land at the same time. How high is the cliff?




2. I know some kinematics equations must be used



3. I am stumped because I don't know the final velocity the height or the time just the difference in time between the two
 
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adidab12 said:
1. To determine how high a cliff is, a llama farmer drops a rock, and then 0.800 s later, throws another rock straight down at a velocity of −10.0 m/s. ]


What is your sign convention? Why the velocity is negative?
 
i don't know what you mean by sign convention but velocity is negative because it is traveling downwards
 
adidab12 said:
i don't know what you mean by sign convention but velocity is negative because it is traveling downwards

In that case, what is the direction of acceleration due to gravity, g?
 
-9.8
 
d=d0+v*t+1/2at2
d=d0+v*(t-.800s)+1/2a(t-.800s)2

First rock,
d0=0
V=0
a=9.81
d=1/2at2

Second rock,
d0=0
d=10m/s*(t-.800s)+1/2*9.81*(t-.800)2

I used calculator to find when these to intersect.
y1=1/2at2
y2=10m/s*(t-.800s)+1/2*9.81*(t-.800)2
Calc->Intersect
I got x =2.26sec y = 25.02 m
 

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