What Is the Height of the Pole in This Trigonometry Problem?

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The discussion focuses on calculating the height of a pole using trigonometric principles. A man who is 1.5 meters tall stands 4 meters away from the pole, with an angle of elevation of 30 degrees. The height of the pole, denoted as P, is derived using the tangent function: P = 4 tan(30°) + 1.5, resulting in an approximate height of 3.81 meters. The conversation also explores alternative formulations using the tangent and cotangent functions to express the relationship between the pole's height and the man's height.

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mathdad
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A little review of trigonometry.

A man 1.5m tall is standing 4m away from a pole. If the angle of elevation of the top of the pole is 30 degree,
calculate the height of the pole.

My set up is here.

Let x = height of pole

1.5 + tan30 = x/4

4*tan(30) = x + 4(1.5)

Correct?
 
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I would let P (in m) be the height of the pole, and let x be the difference between the height of the pole and the height of the man, i.e.:

x = P - 1.5

or:

P = x + 1.5

Constructing a right triangle, we obtain:

tan(30°) = x/4 which implies x = 4 tan(30°)

And so we have:

P = 4 tan(30°) + 1.5

$$P=\frac{4}{\sqrt{3}}+\frac{3}{2}=\frac{8+3\sqrt{3}}{2\sqrt{3}}=\frac{9+8\sqrt{3}}{6}\approx3.809401076758503$$
 
How about tan(30) = 4/(x - 1.5)?
 
RTCNTC said:
How about tan(30) = 4/(x - 1.5)?

You would want:

tan(30°) = (x - 1.5)/4

The tangent function represents the ratio of opposite/adjacent in a right-triangle. :D
 
MarkFL said:
You would want:

tan(30°) = (x - 1.5)/4

The tangent function represents the ratio of opposite/adjacent in a right-triangle. :D

How about cot(30) = 4/(x - 1.5)?
 
RTCNTC said:
How about cot(30) = 4/(x - 1.5)?

Yes, that would be correct. :D
 
Cool. Now back to precalculus. Check out my absolute value questions.
 

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