What is the Impulse Delivered by an Elevator to a Moving Package?

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SUMMARY

The impulse delivered by an elevator to a moving package is 3600 Ns upward when lifting a 1200N package over a distance of 10 meters in 3 seconds. This conclusion is based on the understanding that while the elevator moves at a constant speed, the net force acting on the package is zero due to the balance of forces. The relevant equation used is the change in momentum equals net force multiplied by the time interval.

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Homework Statement


Moving at a constant speed, an elevator lifts a 1200N package 10m in 3 sec. During this time, the impulse delivered to the package by the elevator floor is
a) zero
b) 12000 Nm up
c) 3600 Ns up
d) 12000 Ns up


Homework Equations


change in momentum = net Force*time interval


The Attempt at a Solution


zero b/c if it's moving at constant speed, the acceleration is zero. therefore, net force = zero.
 
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There are two forces acting on the body -- reaction force of the elevator floor acting upward, and the weight of the body acting downward. The net force and the net impulse is zero, but the question specifically asks for the impulse delivered to the package by the floor, and thus should be 3600 Ns up. (Note that impulse is a vector quantity.)
 
Thanks ShootingStar. You've been a great help. :smile:
 

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