What Is the Instantaneous Velocity at t=3.0 s?

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SUMMARY

The instantaneous velocity of a particle at t=3.0 seconds is calculated using the formula for instantaneous velocity, defined as dx/dt. In the provided graph, a displacement of 8 meters corresponds to 3 seconds. The correct approach involves drawing a tangent line at t=3 seconds to determine the slope, which represents the instantaneous velocity. If the initial position x0 is zero, the velocity v is calculated as 8/3 m/s.

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BeckyStar678
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Homework Statement


find the instantaneous velocity of the particle described in figure 1.1 at the following time a.) t=3.0 s.



Homework Equations


instantaneous velocity equals dx/dt
in the graph, 3 seconds of time is equal to 8 meters.



The Attempt at a Solution



so would the answer just be the derivative of 8/3? i don't get how to use the formula. because then the answer would just be zero, right?
 
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BeckyStar678 said:

Homework Statement


find the instantaneous velocity of the particle described in figure 1.1 at the following time a.) t=3.0 s.



Homework Equations


instantaneous velocity equals dx/dt
in the graph, 3 seconds of time is equal to 8 meters.



The Attempt at a Solution



so would the answer just be the derivative of 8/3? i don't get how to use the formula. because then the answer would just be zero, right?

dx/dt gives you the slope of the tangent drawn to point at which you need the instantaneous speed. I presume that you have a displacement versus time graph. Draw a tangent to the point at t=3 and fine the slope of the tangent.
Otherwise more accurately, if you could express displacement as a function of time from the structure of the graph an then differentiate it, it would be better.
regards,
Ritwik
 
if the acceleration is zero (a=0) then x=v*t+x0 so the answer is 8=v*3+x0 and if x0=0 then the answer is v=8/3
and also v=dx/dt then dx=v*dt and if you integrate this equation you will get x-x0=v*t
 

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