What is the length of the catapult?

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SUMMARY

The discussion centers on calculating the length of a catapult used to launch a jet fighter plane, which reaches a final velocity of 42 m/s in 2.0 seconds. The acceleration is determined to be 21 m/s², derived from the formula Vf = Vi + at. Using the kinematic equation Vf² = Vi² + 2ad, the length of the catapult is calculated to be 42 meters. The solution provided by the user, Otis, is confirmed as correct by another participant.

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FilthyOtis
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Homework Statement



A Jet fighter plane is launched from a catapult on an aircraft carrier. It reaches a speed of 42 m/s at the end of the catapult, and this requires 2.0s. Assuming the acceleration is constant, what is the length of the catapult?



Am I looking at this correctly?

final velocity(Vf) is 42 m/s

initial velocity(Vi) is 0 m/s

time(t) is 2.0 s

acceleration(a) is 21 m/s^2 (I'm assuming this because if it started from rest and after 2 seconds is traveling 42 m/s than the acceleration must be half of that? or am I way off? )


Here's my solution, Vf^2 = Vi^2 +2ad

(42 m/s)^2 = 0 + 2(21 m/s^2)d

d = 42^2 / 42 = 42m

Am I doing this correctly? Thank you for any help in advance.

- Otis
 
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