What is the mass of the cylinder?

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Homework Help Overview

The problem involves a solid cylinder with a massless string wrapped around it, from which a block of mass 2.0 kg hangs. The block falls a distance of 82 cm in 2.0 seconds, and the task is to calculate the mass of the cylinder using principles of dynamics and rotational motion.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to determine the force exerted on the cylinder and the acceleration of the block. There is consideration of how the lack of a given radius complicates the calculations. One participant attempts to derive the mass of the cylinder using torque equations, while another questions the geometry of the setup.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding how to share visual information, and there is a mix of confidence in the proposed solution and uncertainty about its correctness.

Contextual Notes

Participants express a need for more information about the geometry of the setup, indicating that visual aids may be necessary to clarify the problem. There is also mention of waiting for attachment approvals, which may affect the flow of discussion.

magnummd
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Homework Statement



Problem: A massless string is wrapped around a solid cylinder as shown in the diagram at the right. A block of mass m = 2.0 kg hangs from the string. When released, the block falls a distance of 82 cm in 2.0 s. Starting with a free-body diagram, calculate the mass of the cylinder.

Homework Equations



d = volt + 0.5at^2
Tension = ma - mg
Torque = (I)(alpha) = F(r)

The Attempt at a Solution



Conceptually, I figure I need to find the force being exerted on the wheel, and the acceleration. That will leave nothing but the mass to be determined. But the fact that it's rotational, throws a wrench into it, especially since no radius is provided.

using d = volt + 0.5at^2 we get a = 0.41 m/s^2 for the block.
Tension is therefore, 18.78 N in the opposite direction of the block's movement and is the force being exerted on the wheel (I think).

Torque = 18.78(r) = 0.5Mr^2(a/r)

If my approach is right, I need M, but r is in the way. What to do?
 
Last edited:
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magnummd said:
Torque = 18.78(r) = 0.5Mr^2(a/r)

If my approach is right, I need M, but r is in the way. What to do?

Wait a minute... the radii all cancel... therefore M = 37.56/0.41 = 91.6 kg

Did I figure it out, or did I just dig myself into a deeper hole? Help please!
 
Could you give more information about the geometry?
 
I don't really know where I could attach a photo of it, but it essentially looks like a string hanging off a pulley with a mass on the end.

Any suggestions on how I can show it to you?
 
Last edited:
When you make a new reply below "submit reply" look for a button called "Manage Attachments".
 
Sweet thanks! Here it is:
 

Attachments

  • Assignment Question Diagram.JPG
    Assignment Question Diagram.JPG
    2.5 KB · Views: 740
I'm new to this forum but just a general hint i post my pictures on photobucket.com and then just click the image button where i want it in the post and paste in the link ...
 
  • #10
Anything guys (or ladies)?

The attachment's been approved. So does anyone have any ideas?
 
  • #11
Your solution looks good to me.
 
  • #12
Alright then! Thanks a lot!
 

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