What Is the Maximum Force Before the Top Block Slides Off?

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The maximum force before the top block (3M) slides off the stack of blocks on a frictionless surface is 107 N. The system consists of three blocks with masses M (7 kg), 2M, and 3M, where a force F of 28 N is applied to the block M. The friction coefficients between blocks 2M and 3M are μs = 0.26 and μk = 0.15. The calculations involve determining the static friction force that prevents the sliding of the top block.

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Three blocks (M, 2M, and 3M) are placed in contact on a horizontal frictionless surface. A constant force of magnitude F is applied to the box of mass M. There is friction between the surfaces of blocks 2M and 3M (μs = 0.26, μk = 0.15) so the three blocks accelerated together to the right.
The blocks are set up so that M and 2M are side by side with 3M on top of 2M.
M = 7 kg
F = 28 N

I tried using basic kinematic and friction equations, but haven't been able to get the correct answer which is 107 N. Help is greatly appreciated.
 
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Just realized I hadn't posted the actual question:
What is the maximum force F that can be applied, before the 3M block slides off?
 

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