wernzj
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Three blocks (M, 2M, and 3M) are placed in contact on a horizontal frictionless surface. A constant force of magnitude F is applied to the box of mass M. There is friction between the surfaces of blocks 2M and 3M (μs = 0.26, μk = 0.15) so the three blocks accelerated together to the right.
The blocks are set up so that M and 2M are side by side with 3M on top of 2M.
M = 7 kg
F = 28 N
I tried using basic kinematic and friction equations, but haven't been able to get the correct answer which is 107 N. Help is greatly appreciated.
The blocks are set up so that M and 2M are side by side with 3M on top of 2M.
M = 7 kg
F = 28 N
I tried using basic kinematic and friction equations, but haven't been able to get the correct answer which is 107 N. Help is greatly appreciated.