What Is the Maximum Forward Force Before Car Wheels Spin?

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SUMMARY

The maximum forward force before car wheels spin is determined by the static friction between the tires and the road. Given a coefficient of friction (μ) of 0.06 and a car mass of 500 kg, the maximum frictional force is calculated as 150 N. The forward force exerted by the car engine, calculated using the formula F = m*a, results in 2500 N. Therefore, the net forward force before wheel spin occurs is 2350 N, which is the effective force available for acceleration.

PREREQUISITES
  • Understanding of Newton's second law of motion (F = m*a)
  • Knowledge of static friction and its coefficient (e.g., coefficient of friction of 0.06)
  • Basic concepts of force and acceleration in physics
  • Familiarity with the relationship between frictional force and normal force
NEXT STEPS
  • Study the principles of static vs. kinetic friction in automotive applications
  • Learn about tire dynamics and how different surfaces affect traction
  • Explore advanced vehicle dynamics simulations using tools like MATLAB or Simulink
  • Investigate the effects of weight distribution on vehicle acceleration and braking
USEFUL FOR

Automotive engineers, physics students, and anyone interested in understanding vehicle dynamics and tire performance.

kokodile
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Homework Statement


Car tires have a coefficient of friction of .06 and the tires are accelerating at 5/ms^2. If the total mass of the car is 500 kgm, calculate the forward force exerted by the car engine.

Homework Equations


I know that .06 is Mu and Mu is equal to friction/normal force. And I know that force=m*a.

The Attempt at a Solution


I sometimes get confused with the difference forces. I calculated the forward force to be 2500 N by doing f=(500)(5). But I'm not sure if that's right because isn't this equation only for normal force? Can it also be for forward force?
Then I did .06=friction/2500 and I got 150 N for friction. So if friction is 150 N and forward force is 2500 then the net forward force exerted by the car engine would be 2350 N.

Is this correct? I have a feeling it's not...
 
Physics news on Phys.org
Friction between road and tyres is the only force accelerating the car.
The car engine can push the wheels on the road only as hard as the static friction between tyres and the road allows - any more and the wheels will spin.
You are being asked to work out this maximum amount of force before the wheels spin.
 

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