What is the Maximum Horizontal Distance for a Rooftop Escape?

[xupe33jrm]

Homework Statement

A criminal is escaping across a rooftop and runs off the roof horizontally at a speed of 5.7 m/s, hoping to land on the roof of an adjacent building. Air resistance is negligible. The horizontal distance between the two buildings is D, and the roof of the adjacent building is 2.0 m below the jumping-off point. Find the maximum value for D.

The Attempt at a Solution

s=ut + .5at^2, so t^2 = 2s/g = (2 x 2)/9.81, t=0.4077, then do .4077 x 5.7 = 2.324 m, but that answer is wrong. I have no idea what is going on here, please help.

 

[Spinnor]

Homework Statement

A criminal is escaping across a rooftop and runs off the roof horizontally at a speed of 5.7 m/s, hoping to land on the roof of an adjacent building. Air resistance is negligible. The horizontal distance between the two buildings is D, and the roof of the adjacent building is 2.0 m below the jumping-off point. Find the maximum value for D.

The Attempt at a Solution

s=ut + .5at^2, so t^2 = 2s/g = (2 x 2)/9.81, t=0.4077, then do .4077 x 5.7 = 2.324 m, but that answer is wrong. I have no idea what is going on here, please help.

Check your math, did you take the square root of (2 x 2)/9.81?

 

[xupe33jrm]

It was my math, thanks! I could not figure out what I was doing wrong!