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Height and horizontal distance of a projectile

  • #1
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1. The problem: I need to find the height and horizontal distance reached by a projectile given only the vertical and horizontal velocities. Vv=120m/s Vh= 30m/s this is for an algebra based physics class, I'm very new to this stuff.


Homework Equations

: V=at+Vo
X=1\2at^2 + Vo + Xo [/B]


The Attempt at a Solution

: I think I was able to figure out the vertical height and time, getting t=12 and height as x=720
but I have no idea where to go from here to find horizontal distance or anything else that would be necessary to finish the problem. Also, we are using 10m/s instead of 9.8m/s for the acceleration caused by gravity. I just need help with what the next step would be to figuring out the rest of the problem, do I just plug the numbers back into the formula in some way? I've just started taking physics, and I have no idea what I'm doing. Thanks in advance.[/B]
 

Answers and Replies

  • #2
haruspex
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X=1\2at^2 + Vo + Xo
X=1\2at^2 + Vo t + Xo
There are two ways you could find the horizontal range. You could consider the horizontal distance to the reach the highest point and use symmetry, or you could use your equation to find when the vertical height becomes zero again.
 
  • #3
Suraj M
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getting t=12 and height as x=720
This time you have got, is it for the whole path or just midway
You already finished the important part, now, do you think the horizontal velocity would change or remain constant?why? from there you can actually consider the horizontal motion as 1-D.
 

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