What is the maximum horizontal distance it can jump?

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Homework Help Overview

The problem involves a flea's jump, specifically examining its maximum vertical height of 1 cm and the corresponding time spent in the air. The inquiry extends to the time of flight at a 45° launch angle and the maximum horizontal distance achievable during the jump.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of time spent in the air for both vertical and angled jumps, with some attempting to derive initial velocity from given parameters. There are questions about the accuracy of initial assumptions and calculations.

Discussion Status

Some participants have expressed confusion regarding their calculations, while others have attempted to clarify the process for determining time and distance. There is no explicit consensus on the methods used, but guidance has been offered regarding the need to calculate time to the peak of the jump first.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may impose specific methods or equations to be used. There are indications of varying interpretations of the problem setup and calculations.

the.flea
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[SOLVED] The Flea

Homework Statement


A flea, jumping with its highest possible initial speed, can jump to a maximum vertical height of 1 cm. What is
the time spent in the air by the flea during the vertical jump? What would be the time spent in the air if the flea
were instead to leave the ground at an angle of 45° to the horizontal? What is the maximum horizontal distance
it can jump? Answer: 0.09 s, 0.063 s, 0.0196 m

Homework Equations


d=V2t-(1/2)at

The Attempt at a Solution



a)d=0.01m, a=g, v2=0
d=V2t-(1/2)at
0.01=-4.9t^2
t=0.045s *2
t=0.09s
b) tried finding initial velocity from part 1
 
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The initial velocity of the fly v2 is not zero. you made a lot of errors and still managed to get the right answer for the first part.
To solve the rest of the problem you should first have calculated the time to the top of the jump from v = v2 - at at the top of the jump v = 0. then you can get the initial velocity from d = (v_2)t - at^2
 
thanks i get it now
 
u got it solved...!?
i need help still can't figure it out i only get .019780 ... or something like that (just replace the 6 in the package with a 7) and for the other part i get .057 or something like that
 

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