What Is the Minimum Speed Required to Catch a Car Thief?

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SUMMARY

The discussion revolves around calculating the minimum speed required for a second car to catch a car thief traveling at 160 km/h towards point 0. The thief starts from point 30 and reaches point 22 after 3 minutes. To catch the thief before he reaches point 0, the second car must cover the distance in less time than the thief. The key equations derived include the thief's speed equation and the second car's speed equation, emphasizing the need for unit conversions and time calculations.

PREREQUISITES
  • Understanding of average speed calculations
  • Familiarity with unit conversions (km/h to km/min)
  • Basic knowledge of algebraic equations
  • Concept of relative motion in one-dimensional space
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  • Learn how to convert speeds between different units (e.g., km/h to km/min)
  • Study the concept of relative velocity in physics
  • Practice solving linear equations involving time and distance
  • Explore real-world applications of motion equations in pursuit scenarios
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This discussion is beneficial for students studying physics, particularly those focusing on motion and speed calculations, as well as anyone interested in solving real-world problems involving pursuit dynamics.

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Homework Statement



There is one car which got stolen which goes from the point 30 in the negative sense of the "x" axe towards the point 0 and has a constant speed of 160 km/h. Another person notices the stealing 3 minutes later and takes another car to catch the stealer. What must be the minimal speed fo the car to catch the stealer before he reacher the point 0 ? (This is all one dimension, btw)[/B]

Homework Equations



average speed on x = delta x / delta t[/B]

The Attempt at a Solution



I found the following two equations :
-160= (x -22)/t (The stealer reaches the point 22 3 minutes later)

Vx= (x-30)/t (The guy who notices he got stealer)

I don't know what to do at this point :/ A hint would be good. Thank you
 
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astrololo said:

The Attempt at a Solution


I found the following two equations :
-160= (x -22)/t (The stealer reaches the point 22 3 minutes later)

Vx= (x-30)/t (The guy who notices he got stealer)

I don't know what to do at this point :/ A hint would be good. Thank you

You need to include the units.
There is km/hr and minutes involved so some conversion is necessary.
It's unclear what significance you think 'point 22' has, it's not important where the first car is when the second car starts. All that matters is that they both reach x=0 at the same time.

The first car starts 30km from the origin, how long does it take to travel 30km at 160km/hr? (v & d known, t unknown)
How fast must the second car go to cover that same distance in 3 minutes less time and meet the first car at x=0? (t & d known, v unknown)
 

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