Distance and Acceleration for One Car to Catch Another

  • Thread starter hitemup
  • Start date
  • #1
81
2

Homework Statement


[/B]
You are traveling at a constant speed vM, and there is a car in front of you traveling with a speed vA. You notice that vM>vA, so you start slowing down with a constant acceleration a when the distance between you and the other car is x. What relationship between a and x determines whether or not you run into the car in front of you?


Homework Equations



x = v0*t - 1/2*a*t^2

The Attempt at a Solution


[/B]
After a time t, the distance between the cars must be something larger than x if they don't want to crash, so:

vM*t-1/2*a*t^2 - vA*t > x

t(vM-1/2*a*t-vA)>x
(vM-vA-1/2*a*t)>x/t

What should be the next step after this?
 

Answers and Replies

  • #2
NTW
302
26
I believe you are complicating things too much. It's simple... A uniform deceleration has to cancel the relative velocity within a given distance...

And I would choose another equation...
 
  • #3
16
0
we can easily find by using...
s=u+at
 
  • #4
NTW
302
26
Remember: you know two things, that are enough: 1) the difference of velocity with respect to the other car Vm - Va. Let's call it U. 2) you also know the distance x to the other car when you start braking with a uniform negative acceleration a.

Thus, you should use a equation that gives a as a function of U and x... That is, acceleration as a function of velocity and space. You probably know the equation as giving velocity as a function of space and acceleration.

Just solve for acceleration...
 
  • #5
81
2
Remember: you know two things, that are enough: 1) the difference of velocity with respect to the other car Vm - Va. Let's call it U. 2) you also know the distance x to the other car when you start braking with a uniform negative acceleration a.

Thus, you should use a equation that gives a as a function of U and x... That is, acceleration as a function of velocity and space. You probably know the equation as giving velocity as a function of space and acceleration.

Just solve for acceleration...

http://www.sketchtoy.com/63345550

I've done this. But what can be said for a and x just looking at this equation?
(vM- vA)^2 /(2a) must be less than x for cars not to crash?
 
  • #6
NTW
302
26
The negative acceleration to be calculated by a = U2/2*x is exactly the necessary to avoid contact... More deceleration will equalize the speeds earlier, keeping the distance, and less deceleration would result in a crash...
 
Last edited:

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