How Strong Does a Fishing Line Need to Be to Stop a Drifting Salmon?

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SUMMARY

The minimum strength required for a fishing line to stop a drifting salmon weighing 78 N over a distance of 13 cm, with an initial horizontal velocity of 3.1 m/s, can be calculated using the equation Vf^2 = V0^2 + 2a(x - x0) alongside Newton's second law, F = ma. The problem involves determining the necessary deceleration and subsequently the force exerted on the line. This analysis confirms that understanding constant acceleration equations is crucial for solving such physics problems.

PREREQUISITES
  • Understanding of constant acceleration equations
  • Knowledge of Newton's second law (F = ma)
  • Basic principles of kinematics
  • Ability to perform unit conversions (e.g., from cm to meters)
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  • Study the derivation and application of kinematic equations in physics
  • Learn about the relationship between force, mass, and acceleration in various contexts
  • Explore practical applications of physics in fishing and sports
  • Investigate the effects of different materials on fishing line strength
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Students studying physics, particularly those focusing on mechanics, as well as fishing enthusiasts interested in the technical aspects of fishing gear and line strength.

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Homework Statement


The tension at which a fishing line snaps is commonly called the line's “strength.” What minimum strength is needed for a line that is to stop a salmon of weight 78 N in 13 cm if the fish is initially drifting horizontally at 3.1 m/s? Assume a constant deceleration.


Homework Equations


I need to use constant acceleration equations...so: v=V0+at, x-x0=v0t+(1/2)at^2...there are 3 other equations for constant acceleration but I don't think i have learned them yet.

The Attempt at a Solution


I am pretty stuck on this one as I have no idea which equation to use and what to do after that to find the solution
 
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I got it with the help of a friend using Vf^2=V0^2+2a(x-x0) and F=ma
 

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