- #1

LCSphysicist

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- TL;DR Summary
- I would appreciate if you explain to me how to get the Minkowski metric tensor's trace.

I am trying to follow the rule, that is, raising an index and the contract it.

Be ##g_{\mu v}## the metric tensor in Minkowski space.

Raising ##n^{v \mu}g_{\mu v}## and then, we need now to contract it.

Now, in this step i smell a rat (i learned this pun today, hope this mean what i think this means haha)

Can i simply say that ##\mu## is an index using Einstein notation? I am a little confused how to contract this and then reduced it to delta kronecker, which, in the end, will give us the trace equal four.

Be ##g_{\mu v}## the metric tensor in Minkowski space.

Raising ##n^{v \mu}g_{\mu v}## and then, we need now to contract it.

Now, in this step i smell a rat (i learned this pun today, hope this mean what i think this means haha)

Can i simply say that ##\mu## is an index using Einstein notation? I am a little confused how to contract this and then reduced it to delta kronecker, which, in the end, will give us the trace equal four.