What is the moment of inertia of the flywheel?

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Homework Help Overview

The problem involves calculating the moment of inertia of a flywheel used in an energy storage system, given its maximum energy storage capacity and rotational speed.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conversion of rotational speed from revolutions per minute to radians per second and its application in the kinetic energy equations. There is uncertainty regarding the correct interpretation of energy units and their relationship to kinetic energy components.

Discussion Status

Participants are actively engaging with the problem, attempting calculations and questioning their results. Some guidance has been offered regarding unit conversions and the relationship between total energy and kinetic energy components.

Contextual Notes

There is confusion regarding the conversion of megajoules to joules, with participants clarifying the difference between 4.4 MJ and 4400 J.

bikeeich
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Homework Statement



An energy storage system based on a flywheel (a rotating disk) can store a maximum of 4.4 MJ when the flywheel is rotating at 21,300 revolutions per minute. What is the moment of inertia of the flywheel?

Homework Equations



K= Ktranslational + Krotational
Krot= (1/2)Iω^2

The Attempt at a Solution



I solved 21,300 rev/min to be equal to 2.23E3 rad/s
I then tried to use this as angular acceleration in the Krot equation to solve for moment of inertia and got 1.77E-3 kgm^2, which was incorrect. I'm wondering if I need to set 4400J= Ktrans + Krot, to solve for I (moment of inertia) but if so I can't figure out how to solve for velocity in the Ktrans equation.
 
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bikeeich said:
I solved 21,300 rev/min to be equal to 2.23E3 rad/s
OK.

I then tried to use this as angular acceleration in the Krot equation to solve for moment of inertia and got 1.77E-3 kgm^2, which was incorrect.
Looks like you're off by a few powers of 10. Do that calculation over.

I'm wondering if I need to set 4400J= Ktrans + Krot, to solve for I (moment of inertia) but if so I can't figure out how to solve for velocity in the Ktrans equation.
No, you're on the right track.
 
I tried again and got the same answer. I'm sure I have a stupid mistake somewhere
Is it incorrect that 4.4MJ = 4400 J?
 
bikeeich said:
I tried again and got the same answer. I'm sure I have a stupid mistake somewhere
Is it incorrect that 4.4MJ = 4400 J?

4.4MJ = 4.4x10^6 J. 4400J is 4.4x10^3 J, or 4.4 kJ. :)
 
WOW. I might need to take a break. Thank you for the correction help!
 

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