What is the mutual gravitational force between the Moon and the Sun at 1AU?

Click For Summary
SUMMARY

The mutual gravitational force between the Moon and the Sun at a distance of 1 AU can be calculated using Newton's law of universal gravitation, represented by the formula F = G * (M1 * M2) / R^2. Given the mass of the Sun (Msun = 1.989 x 10^30 kg), the mass of the Moon (Mmoon = 7.35 x 10^22 kg), and the gravitational constant (G = 6.67 x 10^-11), the gravitational force can be determined. The force exerted by the Sun on the Moon is equal to the force exerted by the Moon on the Sun, in accordance with Newton's Third Law of Motion.

PREREQUISITES
  • Understanding of Newton's law of universal gravitation
  • Familiarity with the gravitational constant (G = 6.67 x 10^-11)
  • Knowledge of mass units (kg) and distance units (meters)
  • Basic algebra for rearranging equations
NEXT STEPS
  • Calculate the gravitational force between the Moon and the Sun using the provided formula
  • Explore the implications of Newton's Third Law of Motion in gravitational interactions
  • Investigate the effects of distance on gravitational force using different values of R
  • Learn about gravitational force calculations in multi-body systems
USEFUL FOR

Students studying physics, particularly those focusing on gravitational forces, astrophysicists, and educators looking to explain gravitational interactions in celestial mechanics.

dluv
Messages
1
Reaction score
0
Hello! I came across this website on my quest to find an answer to this physics problem. I read a topic that was a similar problem, but it didn't address my question in particular. So now I'm posting my problem specifically, and thank you in advance for any help!

Homework Statement


a. What is the gravitational force on the Moon from the Sun?
b. What is the gravitational force on the Sun from the Moon?
Use 1AU as distance between the Moon and Sun.

Msun = 1.989 x 10^30 kg
Mmoon = 7.35 x 10^22 kg
1AU = 1.4960 x 10^11 m
G = 6.67 x 10^-11

Homework Equations



[tex] F = \frac{G M_1 M_2}{R^2}[/tex]

The Attempt at a Solution



When using the above equation, I am only able to get the TOTAL gravitational force between objects, not the force of one on the other.

Is there another equation I must use or is there some way to rearrange the variables to get what I want?THANK YOU FOR YOUR HELP!
 
Physics news on Phys.org
[tex]F_m_1 = \frac{Gm_2}{r^2}[/tex]
 
Last edited:
The force of the Sun on the Moon is equal to the force of the Moon on the Sun, and that force is given by the equation you quote.
The equation is saying that the force is mutual (double ended) as in Newton's 3rd Law of Motion.
 

Similar threads

Replies
21
Views
3K
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
21K
  • · Replies 14 ·
Replies
14
Views
6K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K