What is the oxidation state of oxygen in the products of this reaction?

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The oxidation state of oxygen in the products of the reaction 2C2H2 + 5O2 -> 4CO2 + 2H2O is consistently -2. In carbon dioxide (CO2) and water (H2O), oxygen maintains this oxidation state. The reaction involves the oxidation of acetylene (C2H2) to carbon dioxide and water, with oxygen acting as the oxidizing agent. The oxidation number of oxygen does not change during the reaction, remaining at -2 in both products.

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2C2H2 + 5O2 -> 4CO2 + 2H2O


Oxidation: 2C2- -> 4C4+ + 12e-

I am confused to where the reduction products are becuse the oxygens are part of the carbon dioxide and the water. Could someone please help me?
 
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What is oxidation number of oxygen before and after the reaction?

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