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What is the particle's position at that time?

  1. Sep 16, 2007 #1
    #1
    a)particle's acceleration is described by the function ax=(30.0-33.0t) m/s2, where t is in seconds. Its initial conditions are xo=0.00 m and vox=0.00 m/s at t=0.00 s. At what time is the velocity zero again?
    b)What is the particle's position at that time?

    #2
    a)the velocity-versus-time graph is shown for a particle moving along the x-axis. Its initial position is xo=1.40 m at to=0.00 s. What is the particle's position at t=1.50 s if the total time the particle moves is 6.00 s and the maximum velocity is 6.00 m/s?
    b)At t=1.50 s, what is the particle's velocity?
    c)At t=1.50 s, what is the particle's acceleration?
    d)At t=4.50 s, what is the particle's position?
    e)At t=4.50 s, what is the particle's acceleration?

    #3
    The height of a helicopter above the ground is given by h = 2.65t3 , where h is in meters and t is in seconds. After 1.85 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?

    #4
    A car accelerates at 2.25 m/s2 along a straight road. It passes two marks that are 25.1 m apart at times t=4.00 s and t=4.90 s. What was the car's velocity at t=0?

    #5
    a)A parachustist jumps from an airplane and freely falls y=45.2 m before opening his parachute. Thereafter, he decelerates at a=1.97 m/s2. As he reaches the ground, his speed is 3.22 m/s. How long was the parachutist in the air?
    b) At what height did the parachutist jump from his plane?

    #6
    A very silly person, intent on catching pigeons on the roof of an apartment building, trips and falls a distance of 45.7 m. She lands on a metal garbage can, crushing it to a depth of 0.463 m and walks away without having been seriously hurt. What acceleration did she experience during the collision?
     
  2. jcsd
  3. Sep 16, 2007 #2
    please me me on as much as possible =) i will greatly appreciate it!
     
  4. Sep 16, 2007 #3

    cristo

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    You need to show some work before we can help. We're not here to do your homework for you! So, what thoughts do you have?
     
  5. Sep 16, 2007 #4
    like these are the question i dont even know how to approach.. can you atleast give me hints or something and i work my way through them?
     
  6. Sep 16, 2007 #5

    cristo

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    Staff Emeritus
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    For 1, use the fact that a=dv/dt. You have initial conditions, so should be able to solve the problem.

    You still need to show effort before you get any help-- forum rules!
     
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