What is the percent of energy lost in an inelastic collision?

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SUMMARY

The discussion centers on calculating the percent of kinetic energy lost in an inelastic collision involving two blocks. The user correctly identifies the formula for energy loss as [(K initial - K final)/K(initial)]*100. It is established that the final kinetic energy (K final) must account for the combined mass of both blocks after the collision, as they move together. The user confirms understanding after clarification on this point.

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percent of energy lost?

I'm confused... I have a case where block 1 moves with certain velocity, hits block 2 (that is at rest) and sticks to it - inelastic collision. Now, the problem is that I have to find the percent of energy (kinetic) that the first block has lost. I know that the formula is [(K initial - K final)/K(initial)]*100, but wha I'm wandering about is whether K(final) should include the mass of block 2 or not?
They are actually one mass after collision, but the question asks for the lost of energy of block 1. Can you somehow explain this to me? Thank you!
 
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Yeah, calculate the final kinetic energy with the combined mass.
 
Thanks, I got it right!
 

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