What is the physical significance of the commutator in the Virial Theorem?

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SUMMARY

The discussion centers on the physical significance of the commutator in the context of the Virial Theorem, specifically regarding the stationary state |E⟩ and its relationship with the Hamiltonian operator \(\hat{H}\). The commutator \([\hat{r}\bullet\hat{p},\hat{H}]\) is shown to equal \(i\hbar\left(\frac{p^2}{m} - \vec{r}\bullet\nabla V\right)\). The expectation value of this commutator over stationary states is zero, indicating that there is no net change in the system's energy due to the position-momentum relationship, which is crucial for understanding the stability of bound systems in quantum mechanics.

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  • Knowledge of commutators and their significance in quantum mechanics.
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  • Study the derivation of the Virial Theorem for various potential forms, particularly \(V(r) = \alpha r^{n}\).
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maverick280857
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Hi everyone

I have a question regarding a step in the proof of the Virial Theorem.

Specifically suppose [itex]|E\rangle[/itex] is a stationary state with energy [itex]E[/itex], i.e.

[tex]\hat{H}|E\rangle = E|E\rangle[/tex]

Now,

[tex][\hat{r}\bullet\hat{p},\hat{H}] = i\hbar\left(\frac{p^2}{m} - \vec{r}\bullet\nabla V\right)[/tex]

Taking the expectation value of the left hand side over stationary states, we see that

[tex]\langle E|[\hat{r}\bullet\hat{p},\hat{H}]|E\rangle = 0[/tex]

(The Virial Theorem for central potentials then assumes [itex]V(r) = \alpha r^{n}[/itex] and one gets <T> = (n/2)<V>.)

My question is: what is the physical significance of this commutator and what does it mean physically that the expectation of this commutator wrt a basis of stationary states is zero?

Thanks in advance.

Cheers,
Vivek.
 
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