What is the position of a falling ball given drag force and unknown velocity?

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The discussion revolves around calculating the position of a falling ball while considering drag force and an unknown velocity. The drag force is defined as -C * ||v(t)|| * v, where the negative sign indicates it acts opposite to the velocity. Participants debate whether the velocity v should be taken as v(t) or v(t-dt), with some suggesting that v represents a unit vector in the direction of the velocity. The equations for updating velocity and position are provided, emphasizing the need to incorporate both gravitational and drag forces. Clarification on the interpretation of velocity is crucial for accurately plotting the ball's position.
hello337
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Homework Statement


I have to make a plot. This plot must illustrates a position of a ball, which is falling. My problem is that I don't know what v is in this equation.
drag force= -C * ||v(t)|| * v

Homework Equations



To calculate the velocity:
v(t+dt)=v(t)+a(t)*dt
where t is time and dt is Δt

The position:
x(t+dt)=x(t)+v(t)*dt

To find a(t) (the acceleration) I use:
a(t)=F(t)/M

where M is the mass f the ball and F(t):

F(t)=force from gravity + drag force

And drag force is:
drag force= -C * ||v(t)|| * v


The Attempt at a Solution



I have discussed it with some from my class and some say v is v(t-dt) .. other say it is just v(t).
 
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hello337 said:

Homework Statement


I have to make a plot. This plot must illustrates a position of a ball, which is falling. My problem is that I don't know what v is in this equation.
drag force= -C * ||v(t)|| * v

Welcome to Physics Forums.

That looks like it might be a unit vector in the direction of the velocity. I notice that there's a "-" in front of the constant C. That would make the drag force operate in the opposite direction to the velocity, which is expected.
 
Thank you! So you think that v is v(t) ? :)
 
More likely v = v(t)/|v(t)| , making it a unit vector (magnitude of unity).
 
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