What is the predicted de Broglie wavelength of a bullet traveling at 1060 m/s?

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Homework Help Overview

The problem involves calculating the de Broglie wavelength of a bullet with a mass of 39 grams traveling at a speed of 1060 m/s. The context is within quantum mechanics, specifically relating to wave-particle duality.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use the de Broglie equation and calculates momentum using kinetic energy, but expresses uncertainty about their result. Other participants suggest alternative methods for calculating momentum and wavelength, questioning the original poster's approach.

Discussion Status

The discussion is ongoing, with participants providing different methods for calculating the momentum and wavelength. There is no explicit consensus on the correct approach yet, but some guidance has been offered regarding the calculations.

Contextual Notes

Participants are addressing the conversion of mass from grams to kilograms, which is crucial for the calculations. The original poster's calculations are noted to be incorrect, prompting further exploration of the problem.

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Homework Statement


A bullet of mass 39 g travels at 1060 m/s. Although the bullet is clearly too large to be treated as a matter wave, determine what Eq. 38-13 predicts for the de Broglie wavelength of the bullet at that speed?


Homework Equations


de Broglie equation: wavelength = h / p where h is Planck constant and p is the particle's momentum magnitude.


The Attempt at a Solution


p=sqrt(2*m*K) where K=1/2mv^2. I solved K first and got 21,910,200. Then I solved p and got 41,340. Then I solved for wavelength using the de Broglie eq'n and got 1.604 x 10^-38, but this is not the correct answer. Where did I go wrong?? Thanks for your help!
 
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Huh, I'd start by solving for the momentum (3.9 * 10^-2 kg)(1.060 * 10^3 m/s) = 4.134 *10 kg*m/s, then I would recall that p = h/wavelength and solve for the wavelength. It should be a really big number (of the order 10^34 in the mks system).

Good luck.
 
Yeah, hence it becomes 3.9 times 10^-2 kilograms.
 

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