What is the Probability of A' n B' Given A' and A, B, and A n B?

  • Context: Undergrad 
  • Thread starter Thread starter hellokitten
  • Start date Start date
  • Tags Tags
    Probability
Click For Summary
SUMMARY

The discussion focuses on calculating the conditional probability P(A' n B' | A') using the known probabilities P(A), P(B), and P(A n B). The formula derived is P(A' n B' | A') = [1 - P(A u B)] / [1 - P(A)], which simplifies the computation of the probability of the complements of events A and B given A. The participants confirm the correctness of this formula, emphasizing its utility in probability theory.

PREREQUISITES
  • Understanding of basic probability concepts, including conditional probability.
  • Familiarity with set notation and operations in probability, such as unions and intersections.
  • Knowledge of the complement rule in probability.
  • Ability to manipulate and simplify probability expressions.
NEXT STEPS
  • Study the Law of Total Probability to enhance understanding of conditional probabilities.
  • Learn about Bayes' Theorem for applications in conditional probability scenarios.
  • Explore advanced topics in probability theory, such as joint and marginal distributions.
  • Practice solving problems involving conditional probabilities using real-world examples.
USEFUL FOR

Students of statistics, data analysts, and professionals in fields requiring probability calculations, such as finance and machine learning, will benefit from this discussion.

hellokitten
Messages
10
Reaction score
0
Given P(A), P(B), and P(A n B) . Find the P(A' n B' | A')
We know P(AuB) = P(A)+P(B)- P(A n B)
Then
P(A' n B'|A') = P(A' n B' n A' ) / P(A') = P(A' n B') / P(A') = P(A u B)' /P(A') = [1-P(A u B) ]/ P(A') =
[1-P(A u B)] / [1-P(A)] Correct?
 
Physics news on Phys.org
Right
 

Similar threads

  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 47 ·
2
Replies
47
Views
4K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K