What Is the Probability of Zero Cracks in 5 Miles of Highway?

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SUMMARY

The probability of zero cracks in a 5-mile stretch of highway, where cracks follow a Poisson distribution with a mean of two cracks per mile, can be calculated using the formula for Poisson probabilities. Specifically, the probability of zero cracks in one mile is determined and then raised to the fifth power to account for the total distance. However, some participants argue that the assumption of independence in crack occurrence may not hold due to potential uniform distribution of defects along the highway.

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  • Study Poisson distribution applications in real-world contexts
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Statisticians, civil engineers, and anyone involved in infrastructure maintenance and repair assessments will benefit from this discussion.

bartowski
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The number of cracks in a section of interstate highway that are significant enough to require repair is assumed
to follow a Poisson distribution with a mean of two cracks per mile. What is the probability that there are no cracks that require repair in 5 miles of highway?

any help guys? :)
 
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bartowski said:
The number of cracks in a section of interstate highway that are significant enough to require repair is assumed
to follow a Poisson distribution with a mean of two cracks per mile. What is the probability that there are no cracks that require repair in 5 miles of highway?

any help guys? :)

Just because the mean is a small number doesn't mean it's a Poisson process. In addition it's hard to make the argument that the observations are independent. The stretch of pavement was probably laid at the same time by the same method. If there are defects, I would expect the probability of defects has a uniform distribution along the length of the road under constant conditions. For inconstant conditions, you can't assume a constant distribution.

As an a academic exercise in irrelevant statistics, you would find the probability of 0 defects in one mile under the Poisson distribution with a mean of 2 and raise that value to the fifth power. It has nothing to do with the specific problem you described.
 
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