What is the Proper Notation for Inductive Proofs with Multiple Variables?

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SUMMARY

The discussion focuses on the proper notation for inductive proofs involving multiple variables, specifically addressing the confusion that arises when using variables such as n, k, and m. It concludes that while traditional notation often uses 'n' as the iterative variable, it is acceptable to use alternative labels like 'j' or 'l' to avoid confusion. The key takeaway is that clarity in the proof is paramount, and the choice of variable should not introduce unnecessary complexity. Ultimately, the proof structure remains valid as long as the variable usage is clearly defined.

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  • Understanding of mathematical induction
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  • Knowledge of variable notation in mathematical contexts
  • Basic concepts of universal quantification
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jbusc
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Hi, I have to write several inductive proofs for a class.

Typically, 'n' is used to denote the iterative variable in the problem statement. Then I show the case for n = 1 (or however appropriate for the proof) then proceed to show that if valid for n = k, then valid for n = k+1

However, there are more variables now in the given problem statement (using variables n, k, m, etc) which leaves me uncertain as to how to properly label the inductive step variable. I feel re-using n, k, or m would create additional confusion, as it would if I used alternative variable labels that are not traditionally used to refer only to integers (a, b, c, x, y, z, etc)

How should I alleviate this? Am I clear enough? It's kind of hard to describe...
 
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I don't think it will really make a difference as long as it is clear from your proof how you are using the variable, but I guess you could use j, or l if you want to stick the the letters of the alphabet surrounding n, k, and m.
 
You can also use n for the induction variable, or if not n, whatever variable you happen to be inducting on. It's unnecessary complication to use k in the first place. You just argue:
Code:
Assume S(n)
   ...
   S(n+1)
S(n) --> S(n+1) (conditional proof)
for all n, S(n) --> S(n+1) (universal generalization)
Since n is bound by a quantifier outside of the conditional proof, there is no scope conflict.
 
Last edited:

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