What is the purpose of NaBH4 in this coboxalamine alkylation?

  • Thread starter Thread starter Mayhem
  • Start date Start date
AI Thread Summary
The discussion focuses on the role of cobalt in a reaction involving ethyl iodide and the reduction process facilitated by borohydride. It is suggested that borohydride reduces cobalt from Co(III) to Co(I), which becomes a strong nucleophile capable of displacing iodide in an SN2 reaction. There is curiosity about the fate of the bromide substituent, with speculation that hydride binds to bromine, leading to the formation of HBr, but under slightly alkaline conditions, bromide ion may remain. The context includes a mention of the use of NaBH4 stabilized in KOH with methanol as the solvent, and a clarification that the discussion is not strictly about homework but rather pre-lab safety considerations.
Mayhem
Messages
406
Reaction score
306
1649018842712.png

I am unsure what its role is. My intuition is that it somehow creates a reactive, nucleophilic intermediate which can perform SN2 on ethyl iodide, but my knowledge of the Co-Br bond is sparse and I need some pointers.
 
Chemistry news on Phys.org
The borohydride reduces the cobalt from Co(III) to Co(I), which is strongly nucleophilic and displaces the iodide in the alkylation step.
 
  • Like
Likes Mayhem
TeethWhitener said:
The borohydride reduces the cobalt from Co(III) to Co(I), which is strongly nucleophilic and displaces the iodide in the alkylation step.
Thank you very much. What happens to the bromide substiuent?
 
Mayhem said:
Thank you very much. What happens to the bromide substiuent?
I’ve honestly never really thought about it before. I imagine the hydride binds to the bromine, pushing the electron pair from the Co-Br bond onto the cobalt center. So you’ll get HBr out, but these reactions are often done under slightly alkaline conditions, so it’ll probably be bromide ion at the end.
 
TeethWhitener said:
I’ve honestly never really thought about it before. I imagine the hydride binds to the bromine, pushing the electron pair from the Co-Br bond onto the cobalt center. So you’ll get HBr out, but these reactions are often done under slightly alkaline conditions, so it’ll probably be bromide ion at the end.
Yes, the NaBH4 is stabilized in KOH as the solvent is MeOH in this case. I turned in the assignment the other night, so I guess we will just wait and see.
 
  • Sad
Likes TeethWhitener
Homework problems are supposed to be posted in the homework sections.
 
TeethWhitener said:
Homework problems are supposed to be posted in the homework sections.
Eh, these were pre-lab safety schemes. I didn't consider it homework in the traditional sense.
 
Back
Top