What is the Q-value of the β- decay of Ni-65?

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SUMMARY

The Q-value of the β-decay of Ni-65 is calculated to be 2.14 MeV. The decay process is represented by the equation 65Ni -> 65Cu + e-. The calculation involves the atomic masses of Ni-65 (64.9308 amu) and Cu-65 (64.9277 amu), leading to a difference of -0.0025515 amu, which is then converted to energy using the factor 931.5 MeV/amu. The initial attempt at the calculation was incorrect due to the use of an inaccurate mass for Ni-65.

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Homework Statement



Using the atomic masses of 65Ni and 65Cu, calculate the Q-value of the β- decay of 65Ni (in MeV).
Answer = c) 2.14 MeV

Homework Equations



65Ni -> 65Cu + e-

The Attempt at a Solution



64.9308 -> 64.9277 + 0.0005485
Products - Reactants
-0.0025515 * 931.5 = 2.3767

My answer is in the same ball park but not correct. Are my equations correct?
 
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Last edited:
Please put units into your attempt.
 
Also, assuming your masses are in atomic mass units, you have used the wrong mass for Ni-65.
 

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