What is the range of angles for total internal reflection in glass?

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Homework Help Overview

The discussion revolves around the conditions for total internal reflection involving light transitioning between air and glass, specifically with a glass refractive index of 1.48. Participants are exploring the correct application of Snell's law and the implications of angle calculations.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of the critical angle formula and question the initial setup of the problem. There is confusion regarding the indices of refraction and the necessity of subtracting from 90 degrees in angle calculations.

Discussion Status

The discussion is ongoing with participants providing guidance on the interpretation of the problem. Some suggest revisiting the original phrasing and equations, while others express uncertainty about the calculations and assumptions made regarding the indices of refraction.

Contextual Notes

There is mention of imposed homework rules, specifically that calculus should not be used, which may influence the methods discussed. Additionally, some participants question whether there is a typo in the original problem statement.

nst.john
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1. Light traveling in air strikes a glass surface with n = 1.48. For what range of angles will total internal reflection occur?



2. sinΘc = n2/n1



3. I did this equation with air as n2 and glass as n1 and then got Θc=42.5°. After that I subtracted that from the normal (90°) and got 47.5°. Is this the right way to approach this? Just for the record this is for AP Physics B so no calculus should be used. Thank you!
 
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The question seems to have it backwards. It says " Light traveling in air strikes a glass". Shouldn't it be the other way around?

Why are you subtracting if from 90°?
 
I did that because from air to glass it makes the sin then not exist. So switched it and because I switched it I then subtracted the 90 degrees.
 
Switching it changes the question (which may or may not be necessary. May be the original question has a typo. May be not).
Subtracting from 90° makes no sense.
 
Last edited:
So what should I do?
 
nst.john said:
So what should I do?

Go back to the original phrasing of the problem and the original equation,

\sin \left( \theta_c \right) = \frac{n_2}{n_1}
Now the light starts off in the glass. So what's the original index of refraction, n_1 or n_2 ?
 
nst.john said:
So what should I do?

Nothing. You're done. If you conclude there was no typo then, as you said, there is no sinθ, and if there is a typo than you already solved it in the OP, except that you shouldn't subtract your answer from 90°. There is no reason to do that.
 
Ok. Cool then. Thanks a lot
 
light refracts towards the normal when it travels from a rearer medium to a denser medium so how can we see a perfect image in the mirror it also consits of glass? please answer as fast as possible
 
  • #10
Sayed Fahad said:
light refracts towards the normal when it travels from a rearer medium to a denser medium so how can we see a perfect image in the mirror it also consits of glass? please answer as fast as possible
What will happen when it again go out to air? (From a high dense to low dense medium?)
Can you answer this question?
 
  • #11
The ray will bend away from the medium
 
  • #12
But sir there will be a difference as the ray will reflect back from where it is incident.
 
  • #13
Ooooooooh. Ok I got it now. Thanks for everything
 

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