What is the reaction of the floor of the elevator on the boy?

In summary, the floor of the elevator pushes upwards and the boy feels heavier due to the acceleration.
  • #1
rachael
55
0
8 A boy of mass 65 kg stands on the floor of an elevator.
a What is the weight of the boy?
b What is the reaction of the floor of the elevator on
the boy?
The elevator starts to move upwards with an
acceleration of 1.0 m s–2.
c What is now the reaction of the floor of the elevator
on the boy?
After accelerating upwards for 2.0 s the elevator
continues with a constant upwards velocity.
d What is now the reaction of the floor of the elevator
on the boy?
e What would be the difference to your answer to
part c if the elevator had an acceleration of 1.0 m s–2
downwards?



a. i use w=mg
b.i don't understand y the answer remains the same shouldn't it be ma=mg-N, where mg=650 and ma=65?
c,d,e.i don't get these questions
 
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  • #2
for part (a) yeah m g=w and for part (b) since there is no acceleration in the problem then mg=N. for (c) now there is an acceleration so draw a free body diagram of the forces acting on the boy? what direction is the acceleration and how does this effect the boy? this will answer (c) and (d) and (e)
 
  • #3
From your own experience on an elevator, you notice that when the elevator is static, you feel... normal.

When it starts moving up, you feel heavier. After a while you feel normal again. When it's about to stop you feel lighter.

When it starts moving down, you feel lighter. After a while you feel normal again. When it's about to stop you feel heavier.

It is asking you about these concepts. If you feel heavier, indeed you must be "heavier". That is, if you were standing on a scale on the elevator, it would read a weight higher than your usual.

Weight is caused by the reactionary force from whatever it is you are standing on, in this case, the floor of the elevator. While standing, there are two forces acting on you to produce a net force: gravity (pulling downwards) and the floor (pushing upwards). If the elevator is still, acceleration is zero, so what does this say?

Fnet = ma (a = 0)
Fnet = 0

As we discussed, Fnet consists of two forces, gravity and the floor, so:

Fnet = 0
Fnet = Fgrav + Ffloor = 0
Fnet = mg + Ffloor = 0

Can you take it from here?
 
  • #4
thank you...
 

1. What causes the floor of the elevator to react to the boy?

The floor of the elevator reacts to the boy's weight and the force of gravity acting on him.

2. Does the speed of the elevator affect the reaction of the floor on the boy?

Yes, the speed of the elevator can affect the reaction of the floor on the boy. If the elevator is moving at a constant speed, the floor will exert a normal force on the boy. However, if the elevator is accelerating or decelerating, the force exerted by the floor will change accordingly.

3. Why does the floor of the elevator feel different when it is moving?

When the elevator is moving, the boy and the floor are both accelerating, but in opposite directions. This creates a sensation of weightlessness or heaviness, depending on the direction of acceleration. The floor feels different because it is exerting a force on the boy to keep him in place.

4. Is the reaction of the floor on the boy the same in a stationary elevator?

In a stationary elevator, the boy and the floor are not accelerating, so the force exerted by the floor is simply the normal force needed to support the boy's weight. This is the same as the reaction of the floor on any stationary object placed on it.

5. How does the reaction of the floor on the boy change when the elevator is in free fall?

In free fall, the elevator and everything in it are falling with the same acceleration. This means that the floor is not exerting a normal force on the boy, and he will feel weightless. However, if the elevator suddenly stops, the floor will exert a force on the boy to stop his fall, causing him to feel heavy.

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