What is the relationship between force and potential energy in elastic systems?

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    Elastic Energy
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Homework Help Overview

The discussion revolves around the relationship between force and potential energy in elastic systems, specifically focusing on the work-energy theorem as it applies to elastic potential energy in springs.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the need for average force in the context of the work-energy theorem, question the role of calculus in deriving work done by a spring, and discuss the linear variation of force in relation to displacement.

Discussion Status

The discussion includes various perspectives on calculating work done by a spring, with some participants suggesting the use of average force and others questioning the necessity of calculus. There is an ongoing exploration of how potential energy relates to the area under the force-displacement graph.

Contextual Notes

Some participants express a lack of familiarity with calculus, which influences the nature of the explanations and approaches discussed. The conversation also reflects a need to clarify the assumptions regarding the behavior of spring forces.

flazer
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Who can explain me why we need to find an average force in proving theorem work=elastic potensial energy?
 
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If elastic potential energy (lets call it U) is the only energy involved, then W = - U. Remember, in using Hookes law, that if W = force times distance, the spring force is not constant, so you need to use calculus to find the work, or simply note that the spring force varies from 0 to its max value of kx.
 
I do not know calculus so please can someone explaın me wıthout usıng calculus
 
If the initial force in the spring is 0, and the force varies linearly with x (F=kx) as it is stretched, then at its maximum point of stretch , the force is F=kx, where x is at its maximum. So the average force during that period of stretch is just (0 + kx)/2, or F_average =kx/2. Now use that value of force in your work equation to find the work done by the spring.
 
On the graph of F vs. x, the potential energy is equal to the area under the curve between 0 and x. What constant force would have the same area underneath?
 

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