What is the Relationship Between K-Space and Momentum Space in Crystals?

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SUMMARY

The discussion centers on the relationship between k-space (momentum space) and momentum in crystals, particularly through the lens of Bloch's theorem. The equation presented, \(\psi_{n\mathbf{k}}(\mathbf{r})=e^{i\mathbf{k}\cdot\mathbf{r}}u_{n\mathbf{k}}(\mathbf{r})\), illustrates that the vector \(\mathbf{k}\) represents "crystal momentum," which differs from the actual momentum of an electron. It is clarified that while \(\mathbf{k}\) is independent of position \(\mathbf{r}\), the electron's real momentum changes as it moves within the periodic potential of the crystal, a fact captured by the periodic function \(u\).

PREREQUISITES
  • Understanding of Bloch's theorem in solid-state physics
  • Familiarity with quantum mechanics and Schrödinger's equation
  • Knowledge of crystal lattices and periodic potentials
  • Basic concepts of momentum and wave functions
NEXT STEPS
  • Study the implications of Bloch's theorem in solid-state physics
  • Explore the concept of crystal momentum and its distinction from actual momentum
  • Learn about E(k) plots and their significance in band structure analysis
  • Investigate the role of periodic functions in quantum mechanics
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Students and researchers in solid-state physics, quantum mechanics enthusiasts, and anyone seeking to deepen their understanding of the relationship between k-space and momentum in crystalline materials.

seang
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Hi,

I am having trouble understanding some things about k-space or momentum space in a crystal. The trouble began when I was first introduced to the Bloch theorem, a few weeks back.

It is:

\psi_{n\mathbf{k}}(\mathbf{r})=e^{i\mathbf{k}\cdot\mathbf{r}}u_{n\mathbf{k}}(\mathbf{r}).

In this equation, there is k, which is a vector in momentum space (?). Is it also a vector representing the quantum numbers? (i.e., are the momentum space vector components the quantum numbers of a particular solution of Schrödinger's equation?). Does this mean that in an E(k) plot, as you traverse a particular direction of k, you are traversing the quantum states of the system?

Also, the notation suggests that k is independent of r. In a crystal lattice with a periodic potential, if you move an electron around would not its momentum change also? I guess I'm not sure how the momentum and position of a particle in a crystal are independent of each other.

This MUST sound pretty vague, but there is something I'm not quite getting here. Thanks a lot for your help.
 
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seang said:
Hi,

I am having trouble understanding some things about k-space or momentum space in a crystal. The trouble began when I was first introduced to the Bloch theorem, a few weeks back.

It is:

\psi_{n\mathbf{k}}(\mathbf{r})=e^{i\mathbf{k}\cdot\mathbf{r}}u_{n\mathbf{k}}(\mathbf{r}).

In this equation, there is k, which is a vector in momentum space (?). Is it also a vector representing the quantum numbers? (i.e., are the momentum space vector components the quantum numbers of a particular solution of Schrödinger's equation?). Does this mean that in an E(k) plot, as you traverse a particular direction of k, you are traversing the quantum states of the system?

Also, the notation suggests that k is independent of r. In a crystal lattice with a periodic potential, if you move an electron around would not its momentum change also? I guess I'm not sure how the momentum and position of a particle in a crystal are independent of each other.

This MUST sound pretty vague, but there is something I'm not quite getting here. Thanks a lot for your help.

The vector \bold{k} is "crystal momentum" which is not the same as the actual momentum of a particle. The fact that the electron's real momentum will change as it moves about in the crystal is encoded in the periodic function u; if you act with the actual momentum operator -i\nabla on \psi you find a term proportional to \bold{k}, but also a term proportional to \nabla u.
 
I'm having problems with the whole idea of momentum space, at the most elementary level. I would appreciate some help, please.
 

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