What is the resulting product when Si28 is irradiated with fast neutrons?

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SUMMARY

The irradiation of Si28 with fast neutrons results in the formation of Al28 through a nuclear reaction where a fast neutron collides with the Si28 nucleus, ejecting a proton. This process leads to the emission of gamma radiation as Al28 decays back to Si28. The National Nuclear Data Centre provides essential data for identifying the gamma radiation emitted during this reaction, including the energy of the most intense gamma peak.

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  • Nuclear reaction principles
  • Understanding of neutron activation
  • Familiarity with gamma radiation and its measurement
  • Access to the National Nuclear Data Centre resources
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  • Research the specific nuclear reactions involving Si28 and fast neutrons
  • Explore the decay process of Al28 and its gamma radiation emissions
  • Study the data available at the National Nuclear Data Centre for detailed nuclear data
  • Investigate the implications of neutron activation in nuclear physics applications
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Students and researchers in nuclear physics, nuclear engineers, and professionals involved in radiation safety and nuclear material analysis will benefit from this discussion.

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When a target material is irradiated with neutrons, a number of nuclear reactions are possible. For the slow neutron activation of 28Si, 29Si is created. Determine what is created if 28Si is irradiated with fast neutrons. Then, consult the National Nuclear Data Centre (http://www.nndc.bnl.gov/nudat2/) and determine the gamma radiation that will be emitted.

What is the energy of the most intense gamma peak?
(assume the original target nuclei are those which are naturally most abundant)

Similar to another post I just made. I read a little bit that said the reaction of Si28 and fast neutrons can create Al28. The fast neutron fuses with the Si nucleus, knocking out a proton, and then Al-28 decays back to Si-28 by emitting and gamma radiation.
 
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