What is the Role of Calculus in Mathematical Modeling for Physics?

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Discussion Overview

The discussion revolves around the role of calculus in mathematical modeling for physics, exploring how calculus can be applied to various physical phenomena. Participants share examples of differential equations and their relevance to modeling, while also addressing the challenges faced by those with limited mathematical background.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants express excitement about the application of calculus in physics, particularly in modeling motion and electrical phenomena.
  • Others suggest that differential equations can model systems where quantities change smoothly, citing examples like Navier's and Schrödinger's equations.
  • A participant questions how to model complex phenomena like tornadoes using calculus, seeking clarification on the approach.
  • There is a discussion about the necessity of understanding calculus to grasp the explanations provided, emphasizing the importance of defining rates of change.
  • One participant explains that Newton's second law of motion illustrates the usefulness of calculus by relating acceleration to the second derivative of position.
  • Another participant provides an example of nuclear decay as a real-life application of differential equations, explaining the proportional relationship between decay and the number of radioactive atoms.
  • Concerns are raised about the complexity of fluid dynamics and the modeling of tornadoes, noting that these models are not always accurate but are improving.
  • There is confusion regarding mathematical symbols, particularly the notation used in differential equations, with a participant seeking clarification on their meanings.

Areas of Agreement / Disagreement

Participants express a range of understanding regarding calculus and its applications, with some agreeing on the importance of differential equations in modeling while others struggle with the mathematical concepts. The discussion remains unresolved on several points, particularly regarding the modeling of complex phenomena like tornadoes.

Contextual Notes

Participants acknowledge varying levels of mathematical proficiency, which affects their ability to engage with the technical aspects of the discussion. There are also references to specific equations and models that may require further explanation for those less familiar with the subject matter.

Who May Find This Useful

This discussion may be of interest to students and enthusiasts of physics and mathematics, particularly those looking to understand the application of calculus in modeling physical systems.

WARGREYMONKKTL
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Modeling By Calculus?!?

HI
I AM A STDENT WHO REALLY EXCITED OF PHYSICS. ESPECIALLY A BOUT THE MATHS THAT APPLIED IN PHYSICS.
SOMEBODY SAYS THAT WITH CALCULUS WE HAVE HAD A VERY POWERFUL TOOL FOR MODELING.
I HOPE MANY PEOPLE WITH DISCUSS ABOUT THAT IN THIS THREAD SO WE CAN KNOW MORE ABOUT MATH MODELING FOR PHYSICS.
EXAMPLE : HOW CAN WE APPLY DERIVATIVE IN PHYSICS TO FIND VELOCITY OF A MOTION, OR THE INTENSITY OF A CURRENT?
THANKS FOR YOUR PARTICIPATING.
:wink:
 
Physics news on Phys.org
umm pick up any ODE or PDE text or MATH Phys
A good text from the math bio side of things is Lisa Keshet's...though i don't like the fact that the math is mixed in with the bio stuff...she does
organize the book well into ODE/PDE/DynSys/Bifurcation Theory
 
If something changes smoothly and it's rate of change is related to some other quantity of the system which also changes smoothly (such as electromagnetic fields, liquids, populations, gravity, temperature, almost everything in nature) then you can (in theory) model the system using differential equations.

Navier's equation for fluid flow :
[tex](\lambda + 2 \mu) \nabla (\nabla . \mathbf{u}) - \mu \nabla \times (\nabla \times \mathbf{u}) = \rho \frac{\partial^{2} \mathbf{u}}{\partial t^{2}}[/tex]

Schroedinger's equation :
[tex]i\hbar \frac{\partial \psi}{\partial t} = -\frac{\hbar^{2}}{2m}\frac{\partial^{2}\psi}{\partial x^{2}} + V(x)\psi[/tex]

Those two are both partial differential equations which crop up in large amounts of applied mathematics.
 
if you say so how can i model a phenomanon such as a turnado?
will i choose a particle and suggest that it is in side the turnado and use calculus model to set up an equation for that turnado?
i don't get it.
please give me more example.
thanks you
 
AlphaNumeric said:
If something changes smoothly and it's rate of change is related to some other quantity of the system which also changes smoothly (such as electromagnetic fields, liquids, populations, gravity, temperature, almost everything in nature) then you can (in theory) model the system using differential equations.

Navier's equation for fluid flow :
[tex](\lambda + 2 \mu) \nabla (\nabla . \mathbf{u}) - \mu \nabla \times (\nabla \times \mathbf{u}) = \rho \frac{\partial^{2} \mathbf{u}}{\partial t^{2}}[/tex]

Schroedinger's equation :
[tex]i\hbar \frac{\partial \psi}{\partial t} = -\frac{\hbar^{2}}{2m}\frac{\partial^{2}\psi}{\partial x^{2}} + V(x)\psi[/tex]

Those two are both partial differential equations which crop up in large amounts of applied mathematics.
what does those equations mean i don't get it.
i am at a very low level of math.
 
Then wait. No explanation will make sense until you have the math to understand the explanation.

As simply as possible, calculus allows us to define rate of change at a specific instant rather than just average rate of change. That's crucial to any science.
 
The basic equation you'll met first in physics that shows the usefulness of calculus, is Newton's 2.law of motion, F=ma.
"a", the acceleration of the particle, is the second derivative of the position of the particle with respect to time.
Thus, if the forces F are known, you can find the position of the particle as a function of time.
 
WARGREYMONKKTL said:
i am at a very low level of math.
Then you're bitting off more than you can chew in most cases. As HallsofIvy says, I'd explain them then you'd ask what my explanations meant because the notions would not be known to you.
WARGREYMONKKTL said:
if you say so how can i model a phenomanon such as a turnado?
will i choose a particle and suggest that it is in side the turnado and use calculus model to set up an equation for that turnado?
i don't get it.
There are models for tornados, but are extremely complex applications of fluid and thermodynamic equations. A tornado has many different things which affect it (heat, air pressure, humidity, proximity to land, global air currents) and the models we have are not enormously accurate, but getting better all the time.

By the way, fluids aren't (usually) modeled as a collection of particles, but a continuous medium. Only in special cases do fluids get considered to have particle makeup.

A simple example of using a differential equation to model something in real life is nuclear decay of a sample of material like uranium. In this case the amount of radiation given off is proportional to the number of radioactive atoms, so you have

[tex]\frac{dN}{dt} \propto N[/tex]

which gives you the differential equation (when putting in a constant of proportionality)

[tex]\frac{dN}{dt} = -kN[/tex]

The minus is because the sample is shrinking. Solving gives

[tex]N = N_{0}e^{-kt}[/tex]

Therefore radioactive material decays in an exponential fashion. The value of 'k' is different for each material, and relates to the 'half life', which is the commonly quoted quantity when talking about things which decay.
 
HallsofIvy said:
Then wait. No explanation will make sense until you have the math to understand the explanation.

As simply as possible, calculus allows us to define rate of change at a specific instant rather than just average rate of change. That's crucial to any science.
no i don't understand if the sign look like the number 6 in front of t variables in the fluid equation that was provided. what does it mean?
eventhogh my math is not good but i can understand the meaning of the calculus you show.
i just don't understand the physiologically sign( "6" in front of the variable). what is the operation for that sign? i mean what is it mathematical meaning?:bugeye:
 
  • #10
AlphaNumeric said:
Then you're bitting off more than you can chew in most cases. As HallsofIvy says, I'd explain them then you'd ask what my explanations meant because the notions would not be known to you.
There are models for tornados, but are extremely complex applications of fluid and thermodynamic equations. A tornado has many different things which affect it (heat, air pressure, humidity, proximity to land, global air currents) and the models we have are not enormously accurate, but getting better all the time.

By the way, fluids aren't (usually) modeled as a collection of particles, but a continuous medium. Only in special cases do fluids get considered to have particle makeup.

A simple example of using a differential equation to model something in real life is nuclear decay of a sample of material like uranium. In this case the amount of radiation given off is proportional to the number of radioactive atoms, so you have

[tex]\frac{dN}{dt} \propto N[/tex]

which gives you the differential equation (when putting in a constant of proportionality)

[tex]\frac{dN}{dt} = -kN[/tex]

The minus is because the sample is shrinking. Solving gives

[tex]N = N_{0}e^{-kt}[/tex]

Therefore radioactive material decays in an exponential fashion. The value of 'k' is different for each material, and relates to the 'half life', which is the commonly quoted quantity when talking about things which decay.

thank you every much for your careful explanation!
as you talking a bout the radiation of uranium. i want to ask you a question.
we know that Uranium 235 is a radiactive substance. will its radiations make the environment( around the decaying unranium) become radiactive? is there an electromagnetic field around it? if there is a EM-F
what will happen when a photon get into it? you don't need to answer all this . i just reallly interesting in the nuclear physics.
thanks a gain!
<vincent>
 
  • #11
ah um its not a six hehe...its the PDE derivative sign( change of what ever variable follows the sign)...if you don't know that sign then your very far from learning applied math.

as for your tornado equatoin as mentioned above you must decide what your smallest fundamental element in is...like in population dynamics the smalled entity is the individual..."N" would represent the populatoin size and thus dN change in population.

THen you must also decide what physics model(type of motion/force) you will be using in sim. and then you build your eq'n accordingly
 
  • #12
neurocomp2003 said:
ah um its not a six hehe...its the PDE derivative sign( change of what ever variable follows the sign)...if you don't know that sign then your very far from learning applied math.

as for your tornado equatoin as mentioned above you must decide what your smallest fundamental element in is...like in population dynamics the smalled entity is the individual..."N" would represent the populatoin size and thus dN change in population.

:confused: THen you must also decide what physics model(type of motion/force) you will be using in sim. and then you build your eq'n accordingly
:confused:
CAN YOU TELL ME MORE ABOUT THAT?
I DONT'T GET IT.
THANK YOU!
 
  • #13
neurocomp2003 said:
ah um its not a six hehe...its the PDE derivative sign( change of what ever variable follows the sign)...if you don't know that sign then your very far from learning applied math.

as for your tornado equatoin as mentioned above you must decide what your smallest fundamental element in is...like in population dynamics the smalled entity is the individual..."N" would represent the populatoin size and thus dN change in population.

THen you must also decide what physics model(type of motion/force) you will be using in sim. and then you build your eq'n accordingly
CAN YOU GIVE ME SOME INFORMATION ABOUT THAT PDE DERIVATIVE SIGN?
<I AM AN HIGH SCHOOL STUDENT>
 
  • #14
if you are a high school student are you taking calculus

www.mathworld.com everymath students best friend.
 
  • #15
thank you for the link you provide me.
can you please explain the meaning of the Schrödinger's equation. how can we figure out the position of the object at [tex]psi(t,x)[/tex] i hope it working? a "little bit" confusing about it.
 

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