Does 15F Qualify as an sd Shell Nucleus?

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SUMMARY

The discussion centers on whether 15F qualifies as an sd shell nucleus based on the positioning of its last proton and neutron. In 15F, the last proton occupies the 1d5/2 orbit, while the last neutron is in the 1p3/2 orbit. This configuration raises the question of whether both nucleons must reside in the sd shell for the nucleus to be classified as such. The distinction between open and closed sd-shell nuclei is crucial for understanding this classification.

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TL;DR
In nuclear shell model, the shell where the last proton or neutron lies is important. It relates to the property of the nuclei. But what is the definition of sd shell nuclei?
If we call a nucleus a sd shell nucleus, should its last proton and last neutron both lie in the sd shell or just one lies in the sd shell?
For example, 15F, whose proton number is 9 and neutron number is 6. Then the last proton lies in the 1d5/2 orbit and the last neutron lies in the 1p3/2 orbit. So can we call 15F the sd shell nucleus? Thanks a lot!
 
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There is a distinction between open and close sd-shell nuclei, which might give you a hint towards the answer :)
 
malawi_glenn said:
There is a distinction between open and close sd-shell nuclei, which might give you a hint towards the answer :)
I get your point. Thanks very much.
 

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