- #1
Macleef
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What is the solution for a limit problem with an indeterminate form of 0/0?
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The discussion centers on solving a limit problem that results in the indeterminate form 0/0. It emphasizes the application of L'Hopital's rule, which is appropriate for such cases. Initial attempts to simplify the expression using tricks or radicals were unsuccessful. A successful approach involves multiplying by a factor, such as 2 + sqrt(x), to cancel the zero factor in both the numerator and denominator. This method effectively resolves the limit issue.
- #2
Mathdope
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You should have 0/0 not 6/0. In any case, try a trick similar to what you did with the radical in the denominator.
- #3
workerant
- 40
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Well if you plug the four in initially you get:
2-2/(3-3)=0/0
Your trick did not work nor does using the other radical as Mathdope suggests.
But, never fear, 0/0 limits call for one man...
L'Hopital!
Since it is indeterminate form, it is eligible for L'Hopital's rule. That should make it work.
2-2/(3-3)=0/0
Your trick did not work nor does using the other radical as Mathdope suggests.
But, never fear, 0/0 limits call for one man...
L'Hopital!
Since it is indeterminate form, it is eligible for L'Hopital's rule. That should make it work.
- #4
Dick
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workerant said:
Multiplying by 2+sqrt(x) does so work. You can then cancel the factor that's going to zero in the numerator and the denominator.