What is the Speed and Maximum Height of a Pendulum Bob in Motion?

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Homework Help Overview

The discussion revolves around a pendulum problem involving a 1.0 N bob on a 75 cm string. Participants are tasked with determining the speed of the bob at the bottom of its swing and the maximum height it reaches, assuming no air resistance or friction.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss free body diagrams (FBD) and the forces acting on the pendulum bob, including tension and gravity. There is an exploration of how to calculate mass from weight and the implications of tension not equating to the bob's weight. Questions arise regarding the correct application of centripetal force and its relationship to tension and speed.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about forces and discussing the relationships between tension, weight, and centripetal force. Some guidance has been provided regarding the use of the pendulum's weight to find mass and the need to clarify the roles of different forces in the FBD.

Contextual Notes

There is an emphasis on understanding the dynamics of the pendulum system without assuming air resistance or friction, which may affect the calculations. Participants are also navigating the implications of the given values and their relationships in the context of the problem.

kissafilipino
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A 1.0 N pendulum bob is set into motion on a 75 cm long string. At the bottom of the swing the tension is 1.2 N.

a) Deduce that the speed of the bb at the bottom of the swing is 1.2 m s^-2
b) Determine the maximum height the bob will swing assuming no air resistance or friction.


Homework Equations



a) v = 2(pie)r/T = n2(pie)r/t
F = ma
F = m(v^2/r)

The Attempt at a Solution



I first tried setting up a FBD to make it clear, and then after for question B, I simply used F = ma to find the mass, then after finding the mass, the speed:

F = ma
1.2 = m(9.81)
1.2/9.81 = m

F = m(v^2/r)
1.2 = (0.102 (v^2))/(0.0.75)and got 1.06 ms^-1

And for B) I couldn't understand...
 
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kissafilipino said:
I first tried setting up a FBD to make it clear,
Describe your FBD. What forces act on the bob?

and then after for question B, I simply used F = ma to find the mass, then after finding the mass, the speed:

F = ma
1.2 = m(9.81)
1.2/9.81 = m
The tension force does not equal the bob's weight. (You are given the bob's weight.)

F = m(v^2/r)
1.2 = (0.102 (v^2))/(0.0.75)and got 1.06 ms^-1
The tension force does not equal the centripetal force.
 
Doc Al said:
Describe your FBD. What forces act on the bob?


The tension force does not equal the bob's weight. (You are given the bob's weight.)


The tension force does not equal the centripetal force.

1) Well it is basically, force normal, force tension and force gravity. Since centripetal can't be counted as a force, I can't count it in the FBD.
Therefore it would the FBD would have a longer normal force + tension force, and the force of gravity is shorter.


2) Hmm, your right, it doesn't equal the bobs weight, so wouldn't that mean you have to find the mass through gravity from FIRST inputing the 1.0 N pendulum weight?

and to find tension force I'd have to first use the 0.075 m rope radius, and then use F= m(v^2/r)? r = 0.075, and the pendulum weight I found earlier for m? and the 1.2 velocity for v in order to find F?
 
kissafilipino said:
1) Well it is basically, force normal, force tension and force gravity. Since centripetal can't be counted as a force, I can't count it in the FBD.
Therefore it would the FBD would have a longer normal force + tension force, and the force of gravity is shorter.
There's no normal force here. The only forces on the bob are the string tension and gravity.

2) Hmm, your right, it doesn't equal the bobs weight, so wouldn't that mean you have to find the mass through gravity from FIRST inputing the 1.0 N pendulum weight?
Yes. Use the weight of the pendulum to find its mass.

and to find tension force I'd have to first use the 0.075 m rope radius, and then use F= m(v^2/r)? r = 0.075, and the pendulum weight I found earlier for m? and the 1.2 velocity for v in order to find F?
The tension and weight are given; use them to find the centripetal force. Then use the centripetal force to find the speed.
 

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