1. The problem statement, all variables and given/known data A block with a mass m1 is held in place on a table and is attached to a block with mass m2 by a massless inextensible string that passes over a massless pulley with frictionless bearings. The coefficient of static friction between block 1 and the table is μs and kinetic is μk. When block 1 is released, what must be true for block 2 to fall? If that requirement is met, what is the speed of block 1 when block 2 has fallen a distance h? 2. Relevant equations Conservation of energy Ko +Uo -W = Kf + Uf 3. The attempt at a solution In order for block 2 to fall its force due to tension and gravity has to be greater than the difference between the force of block one due to tension and its force of static friction. This is what I think. Thoughts? Also, how would I put this in terms of conservation of energy? For the speed I used (1/2)(m1 +m2)V2 -μkm1gh = (1/2)(m1+m2)gh and solved for V. I used h for the part of work because the same distance block 2 falls is the distance block 1 moves.