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## Homework Statement

An Earth satellite moves in a circular orbit 605 km above the Earth's surface. The period of the motion is 96.6 min.

What is the speed of the satellite?

## Homework Equations

## The Attempt at a Solution

First, I know that it is orbiting 605 km above earth's surface. So, that number plus the radius of earth gives a total for the radius of the motion. That comes out to be about 6976000 meters.

Then, I used the equation:

T = (2pir)/(v)

96.6 = (2pi(6967000)) / (v)

v = 453742.24

But it's marking it as incorrect. Any ideas?