- #1

bored2death97

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## Homework Statement

A wave travels along a spring at speed v0. What will be the speed if the string is replaced by one made of the same material and under the same tension but having twice the radius.

Answer in book says (v0/2)

## Homework Equations

v=√(T/μ)

speed= square root of (tension divided by mu)

μ=m/L

mu= mass/length

## The Attempt at a Solution

With the first equation I filled in the equation for mu. Assuming twice the radius would mean twice the mass, I multiplied mass by 2.

v=√[T/(2m/L)]

v=√(TL/2m)

Then if I were to take the value of 2 out of the square root, I would get v=0.707[√(TL/m)]

Rearrange and get v/0.707

So where did I go wrong??