MHB What Is the Sum of the Series \( \sum_{n=1}^\infty \frac{n}{(n+1)!} \)?

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The series \( \sum_{n=1}^\infty \frac{n}{(n+1)!} \) can be approached by examining the sequence of partial sums, which are \( S_1 = \frac{1}{2} \), \( S_2 = \frac{5}{6} \), \( S_3 = \frac{23}{24} \), \( S_4 = \frac{119}{120} \), and \( S_5 = \frac{719}{720} \). Observing the pattern suggests a limit of 1 as \( n \) approaches infinity. To confirm this, one can use mathematical induction to prove the formula for \( S_n \). Ultimately, the sum of the series converges to 1.
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Find the sum of this series:
$$ \sum_{n=1}^\infty \frac{n}{(n+1)!} $$

I'm really struggling with this one.. Any help will be highly appreciated. Thanks you.
 
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Look at the sequence of partial sums.

$$S_1 = \dfrac{1}{2}$$, $$S_2 = \dfrac{5}{6}$$, $$S_3 = \dfrac{23}{24}$$, $$S_4 = \dfrac{119}{120}$$, $$S_5 = \dfrac{719}{720}$$, etc.

Once you guess the obvious answer for $$S_n$$, you can prove it by induction. Then take the limit as $$n \rightarrow \infty$$
 
There are probably loads of proofs of this online, but I do not want to cheat. Here is my attempt: Convexity says that $$f(\lambda a + (1-\lambda)b) \leq \lambda f(a) + (1-\lambda) f(b)$$ $$f(b + \lambda(a-b)) \leq f(b) + \lambda (f(a) - f(b))$$ We know from the intermediate value theorem that there exists a ##c \in (b,a)## such that $$\frac{f(a) - f(b)}{a-b} = f'(c).$$ Hence $$f(b + \lambda(a-b)) \leq f(b) + \lambda (a - b) f'(c))$$ $$\frac{f(b + \lambda(a-b)) - f(b)}{\lambda(a-b)}...

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