Albert1
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$\sqrt {x}+\sqrt {y}=35$
$\sqrt [3]{x}+\sqrt[3] {y}=13$
find x+y
$\sqrt [3]{x}+\sqrt[3] {y}=13$
find x+y
Albert said:$\sqrt {x}+\sqrt {y}=35$
$\sqrt [3]{x}+\sqrt[3] {y}=13$
find x+y