Albert1
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$\sqrt {x}+\sqrt {y}=35$
$\sqrt [3]{x}+\sqrt[3] {y}=13$
find x+y
$\sqrt [3]{x}+\sqrt[3] {y}=13$
find x+y
The discussion centers on solving the equations $\sqrt{x} + \sqrt{y} = 35$ and $\sqrt[3]{x} + \sqrt[3]{y} = 13$ to find the sum of x and y. By defining $\varphi = x^{\frac{1}{6}}$ and $\psi = y^{\frac{1}{6}}$, the equations transform into $\varphi^3 + \psi^3 = 35$ and $\varphi^2 + \psi^2 = 13$. The solutions yield $\varphi = 2$ and $\psi = 3$, leading to the conclusion that the sum $\chi + \sigma = x + y = 793$.
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Albert said:$\sqrt {x}+\sqrt {y}=35$
$\sqrt [3]{x}+\sqrt[3] {y}=13$
find x+y