What is the Sum of Two Sixth Powers?

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SUMMARY

The discussion centers on solving the equations $\sqrt{x} + \sqrt{y} = 35$ and $\sqrt[3]{x} + \sqrt[3]{y} = 13$ to find the sum of x and y. By defining $\varphi = x^{\frac{1}{6}}$ and $\psi = y^{\frac{1}{6}}$, the equations transform into $\varphi^3 + \psi^3 = 35$ and $\varphi^2 + \psi^2 = 13$. The solutions yield $\varphi = 2$ and $\psi = 3$, leading to the conclusion that the sum $\chi + \sigma = x + y = 793$.

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$\sqrt {x}+\sqrt {y}=35$

$\sqrt [3]{x}+\sqrt[3] {y}=13$

find x+y
 
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Re: operation of root equation

Albert said:
$\sqrt {x}+\sqrt {y}=35$

$\sqrt [3]{x}+\sqrt[3] {y}=13$

find x+y

Setting $\displaystyle \varphi = x^{\frac{1}{6}}$ and $\displaystyle \psi = y^{\frac{1}{6}}$ You obtain...

$\displaystyle \varphi^{3} + \psi^ {3} = 35$

$\displaystyle \varphi^{2} + \psi^ {2} = 13$ (1)

... and the (1) has solutions $\displaystyle \varphi=2\ \psi= 3$ and $\displaystyle \varphi=3\ \psi= 2$ so that is in any case $\displaystyle \varphi + \psi = 5$... Kind regards

$\chi$ $\sigma$
 
Re: operation of root equation

Setting $\chi = \varphi^6$ and $\sigma = \psi^6$, we get $\chi + \sigma = \varphi^6 + \psi^6 = 2^6 + 3^6 = 793$.

Kind regards,

$\text{I}\Lambda\Sigma$
 

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