What is the tension in a hockey puck swung in a horizontal circle?

[Ly444999]

Homework Statement

A hockey puck with mass 200 g is attached to a rope of length 62.0 cm and swung in a horizontal circle against the ice at a rate of 58.0 rpm. Assuming the ice is frictionless, what is the tension in the rope?

Homework Equations

F_T = mω²r

The Attempt at a Solution

58rpm = 6.07 rad/s
200g = 0.2 kg
r = 0.31 m
F_T= (0.2)(6.07)²(0.31)
= 2.28
Is this not how you solve for tension in circular motion?
I was given four answers which none of them match what I calculated 4.57 N, 417 N, 1.65×104 N, 1.09×103 N

 

[PhanthomJay]

Homework Statement

A hockey puck with mass 200 g is attached to a rope of length 62.0 cm and swung in a horizontal circle against the ice at a rate of 58.0 rpm. Assuming the ice is frictionless, what is the tension in the rope?

Homework Equations

F_T = mω²r

The Attempt at a Solution

58rpm = 6.07 rad/s
200g = 0.2 kg
r = 0.31 m
F_T= (0.2)(6.07)²(0.31)
= 2.28
Is this not how you solve for tension in circular motion?
I was given four answers which none of them match what I calculated 4.57 N, 417 N, 1.65×104 N, 1.09×103 N

Yes but you used r = 0.31 m when it is given that the length of the rope is 0.62 m.. So what is the value of r?

 

[Ly444999]

Yes but you used r = 0.31 m when it is given that the length of the rope is 0.62 m.. So what is the value of r?

Oh so the radius isn't half the length of the rope?
Edit: Ok I see why radius isn't half the length never mind and thank you for pointing that out