What Is the Total Impulse on a Sliding Block?

Click For Summary
SUMMARY

The total impulse on a 4.0-kg block sliding at a constant speed of 5.0 m/s is determined by the area under the force-time graph after a horizontal force is applied. The impulse can be calculated using the equation p = ∫F(t) dt. The correct answer for the total impulse is 42 N·s, which reflects the change in momentum resulting from the applied force over the specified time interval.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with impulse-momentum theorem
  • Knowledge of force-time graphs
  • Basic calculus for integration
NEXT STEPS
  • Study the impulse-momentum theorem in detail
  • Learn how to calculate the area under a curve in force-time graphs
  • Explore examples of time-dependent forces in physics
  • Review problems involving momentum conservation
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and impulse, as well as educators looking for practical examples of force applications in real-world scenarios.

enchantress95
Messages
1
Reaction score
0
Momentum impulse physics question, HELP ASAP please!

Homework Statement


A 4.0-kg block slides along a frictionless surface with a constant speed of 5.0 m/s as shown. Two seconds after it
begins sliding, a horizontal, time-dependent force is applied to the mass. The force is removed eight seconds later. The
graph shows how the force on the block varies with time.
• What is the magnitude of the total impulse of the force acting on the block?
• What, approximately, is the speed of the block at t = 10 seconds?



Homework Equations



p= mv
K.E= 1/2*m*v^2

The Attempt at a Solution


p= mv = 20kg*m/s
K.E= 1/2*m*v^2 = 50 J

I was solving this past paper and the answer is 42N but idk how to get tht :s any help wud be appreciated, thanks!
 
Physics news on Phys.org
Welcome to PF;
Please show us your working and how you have been thinking about the problem so far.
That is the best and fastest way to get the help you need.

You are missing an equation - ##p=\int F(t)\; dt##
... which is to say: the change in momentum is the area under the force-time graph.
... what is "specific impulse"?
 

Similar threads

Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
14
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 17 ·
Replies
17
Views
5K
  • · Replies 19 ·
Replies
19
Views
3K
Replies
12
Views
2K