- #1

Austin Gibson

- 47

- 1

## Homework Statement

:A 3.0 kg block starts with a speed of 18 m/s at the bottom of a plane inclined at 41° to the horizontal. The coefficient of sliding friction between the block and plane is

μk = 0.22.

a) Use the work–energy principle to determine how far (in m) the block slides along the plane before momentarily coming to rest.

b) After stopping, the block slides back down the plane. What is its speed (in m/s) when it reaches the bottom? (Hint: For the round trip, only the force of friction does work on the block.)[/B]

## Homework Equations

: 0.5m(v(final)^2 - v(initial)^2) = total work, Fcos(theta)d = work[/B]## The Attempt at a Solution

:I sense that I'm misinterpreting the question.

[/B]