What Is the Value of b If All Roots of the Polynomial Are Positive Real Numbers?

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SUMMARY

The polynomial equation \(x^4 - 8x^3 + 24x^2 + bx + c = 0\) requires that all roots be positive real numbers. The value of \(b\) can be determined using Vieta's formulas, which relate the coefficients of the polynomial to sums and products of its roots. Specifically, for the roots \(r_1, r_2, r_3, r_4\), the conditions lead to the conclusion that \(b = 32\) when all roots are constrained to be positive. This conclusion is supported by the analysis of the polynomial's behavior and the application of the AM-GM inequality.

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anemone
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Here is this week's POTW:

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If all the roots of $x^4-8x^3+24x^2+bx+c=0$ are positive reals, find the value of $b$.

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No one answered last week's POTW.(Sadface)

However, I have decided to give the community another week to attempt at the problem.(Smile)
 
Congratulations to Opalg for his correct solution (Cool) , which you can find below:

If $f(x) = x^4-8x^3+24x^2+bx+c$ has four real roots then its derivative must have three real roots. But $$f'(x) = 4x^3 - 24 x^2 + 48x + b = 4(x-2)^3 + b + 32,$$ and the function $(x-2)^3$ is strictly increasing except at the point $x=2$. So $f'(x)$ can only have three real roots if $b+32 = 0$. Therefore $b = -32$.
 

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