What is the Vapor Pressure of a Urea Solution at 24 C?

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SUMMARY

The vapor pressure of a urea solution at 24°C can be calculated using Raoult's Law. Given that 9 g of urea (molar mass 60.06 g/mol) is dissolved in 10 mL of water, and the vapor pressure of pure water at this temperature is 22.4 mmHg, the solution's vapor pressure will be lower than that of pure water due to the presence of the solute. The calculation involves determining the mole fraction of water and applying Raoult's Law to find the new vapor pressure.

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Homework Statement


If you dissolve 9 g of urea (60.06 g/mol) in 10 mL of water, what is the vapor pressure of the solution at 24 C? Assume the density of water is 1.00 g/mL and the vapor pressure of pure water at 24 C is 22.4 mmHg.


Homework Equations


Henry's Law, maybe? I'm not sure.


The Attempt at a Solution


I have no clue. Help please.
 
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Not Henry's, Raoult's.
 

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