MHB What is the volume of the set of points within 1 unit of a solid box?

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The volume of the set of points within 1 unit of a solid box can be calculated by adding the volume of the box itself, which is LWH, to the volumes of the extensions created by the surfaces, corners, and edges. The surface extensions contribute a total volume of 2(LW + LH + WH), while the corners add a volume of (4/3)π from eight quarter-spheres, and the edges contribute π(L + W + H) from twelve quarter-cylinders. Combining these components gives the total volume as LWH + 2(LW + LH + WH) + π(4/3 + L + W + H). This formula effectively captures the expanded volume around the box. The discussion highlights the geometric reasoning behind the calculations involved.
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Thanks again to those who participated in last week's POTW! Here's this week's problem!

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Problem: Let $B$ be a solid box with length $L$, width $W$, and height $H$. Let $S$ be the set of all points that are a distance at most $1$ from some point of $B$. Express the volume of $S$ in terms of $L$, $W$, and $H$.

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Remember to read the http://www.mathhelpboards.com/showthread.php?772-Problem-of-the-Week-%28POTW%29-Procedure-and-Guidelines to find out how to http://www.mathhelpboards.com/forms.php?do=form&fid=2!
 
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This week's problem was correctly answered by magneto, MarkFL, Opalg, and Pranav. You can find magneto's solution below.

[sp]We will construct the "meta-box" and add the volume.

(a) The volume of the box is $LWH$.

(b) We can extend each of the surface of the box by 1. This creates two blocks of boxes of volume $LW$, $LH$, and $WH$ each. So the total volume would be $2(LW+LH+WH)$.

(c) There are 8 corners each is of $\frac{1}{8}$ of a sphere of radius $1$, so the total volume would be $\frac{4}{3} \pi$.

(d) There are 12 quarter-cylinder, 4 for each dimension of the box. These cylinder's have height of the side of the box, and radius of $1$,
so the total volume is given by $\pi(L+W+H)$.

Therefore, the total volume is $LWH + 2(LW+LH+WH) + \pi (\frac{4}{3} + L + W + H)$.[/sp]